16x+336=x^2

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Solution for 16x+336=x^2 equation:



16x+336=x^2
We move all terms to the left:
16x+336-(x^2)=0
determiningTheFunctionDomain -x^2+16x+336=0
We add all the numbers together, and all the variables
-1x^2+16x+336=0
a = -1; b = 16; c = +336;
Δ = b2-4ac
Δ = 162-4·(-1)·336
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-40}{2*-1}=\frac{-56}{-2} =+28 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+40}{2*-1}=\frac{24}{-2} =-12 $

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